Riddle:
Solve this crazy witch broom wand math riddle…
Please post answer in comments…
Answer:
a) 3 Witches = 45
1 Witch(with 1 wand and 1 broom) = 15
b) 3 Wands = 21
1 Wand = 7
c) 4 brooms = 12
1 broom = 3
Now we have values of 1 broom and 1 wand so lets look at point a) above to calculate value of 1 witch without broom and wand.
1 Witch without broom and wand = 15 – 7- 3= 5
d) 1 broom + 1 witch × 2 Wands = 3 + 5 × 2× 7 =73
Answer is 73.
Many Thanks to Michael Campbell for his answer in comments below. CHEERS.
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the answer to the riddle is not 213. If you look closely at the first equation the witch is carrying a wand and a broomstick in the last equation she is not. So if a wand is 7 and a broom is 3 the witch in the last equation is only worth 15-10 so 5. So the final equation should actually be 1 broom + 1 WItch without wand or broom x 2 wands = 3 + 5 X 2 X 7 = 73. Please correct me if I am wrong in math use of BEDMAS and deduction.
Thanks Michael, you are absolutely correct! We will update the answer today, giving credit to you, ofcourse 🙂
The part where it shows 3 brooms =12, makes the brooms each equal to 4!!! So a witch with no broom or spoon would be 4.
4×7=28. 28+4=32.
The middle broom though has 2 so how can that equal 12? Surely that should be 16 not 12
the middle broom group if you look closely is actually 2 brooms
1broom + 2 brooms + 1 broom= 12 so divide 4 into 12 and the answer is 3 per broom (1 X3)+ (2X3) +(1X3) = 3+6+3 =12
The answer is not 73. Its undefined! It is unclear what the images represent. V+W+V =12. Does the “W” represent two “V”s or a “W”? Broom + Paint brush + broom?